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Meaning of Geometric Progression (GP) and its common ratio, General Term of Geometric Progression (nth term of GP), Derivation for Sum to n terms of a GP, Geometric Mean and its relationship with Geometric Progression, Rules Comparison of Arithmetic Progression and Geometric Progression
| NCERT EXERCISE 9.3 |
Question 1. Find the 20th and nth terms of the G.P. \( \frac{5}{2}, \frac{5}{4}, \frac{5}{8}, …\)
Question 2. Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.
Question 3. The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that \( q^2=ps\).
Question 4. The 4th term of a G.P. is square of its second term, and the first term is – 3. Determine its 7th term.
Question 5. Which term of the following sequences:
(a) \( 2, 2\sqrt{2}, 4, …\) is 128?
(b) \( \sqrt{3}, 3, 3\sqrt{3}, …\) is 729?
(c) \(\frac{1}{3}, \frac{1}{9}, \frac{1}{27}, …\) is \(\frac{1}{19683}\)?
Question 6. For what values of x, the numbers \( -\frac{2}{7}, x, -\frac{7}{2}\) are in G.P.?
Find the sum to indicated number of terms in each of the geometric progressions in Exercises 7 to 10:
Question 7. 0.15, 0.015, 0.0015, … 20 terms.
Question 8. \( \sqrt{7}, \sqrt{21}, 3\sqrt{7}, …\) n terms.
Question 9. \( 1, -a, a^2, -a^3, … n \text{ terms } (\text{ if } a \ne -1)\).
Question 10. \( x^3, x^5, x^7, … n \text{ terms} (\text{ if } x \ne \pm 1)\)
