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Find the value of tan9° – tan27° – tan63° + tan81°

Find the value of tan9° – tan27° – tan63° + tan81°

Dec 28, 2020 | Chapter 3 Trigonometric Functions, Class 11 Maths, videoarticle

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 5: Find the value of tan9° – tan27° – tan63° + tan81° tan9°–tan27° – tan63° + tan81°

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Prove that (sec8θ−1)/(sec4θ−1)=tan8θ/tan2θ

Prove that (sec8θ−1)/(sec4θ−1)=tan8θ/tan2θ

Dec 28, 2020 | Chapter 3 Trigonometric Functions, Class 11 Maths, videoarticle

Topics/Questions discussed in this video: NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 6: Prove that [latex]\frac{sec8\theta-1}{sec4\theta-1}=\frac{tan8\theta}{tan2\theta}[/latex]

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Exercise 3.1 Chapter 3 Trigonometric Functions Class 11 Maths

Exercise 3.1 Chapter 3 Trigonometric Functions Class 11 Maths

Apr 29, 2021 | Chapter 3 Trigonometric Functions, Class 11 Maths, videoarticle

Topics/Questions discussed in this video: 00:21:17 Meaning and origin of Word Trigonometry 00:24:47 Basics of Angles: Positive angles, negative angles, vertex with animations 00:34:57 Measuring an angle00:36:07 Basics of Degree measure, minutes and seconds 00:40:57...

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