NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 5: Find the value of tan9° – tan27° – tan63° + tan81° tan9°–tan27° – tan63° + tan81°
Find the value of tan9° – tan27° – tan63° + tan81°
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Prove that (sec8θ−1)/(sec4θ−1)=tan8θ/tan2θ
Topics/Questions discussed in this video: NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 6: Prove that [latex]\frac{sec8\theta-1}{sec4\theta-1}=\frac{tan8\theta}{tan2\theta}[/latex]
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(Part – 2) Exercise 2.1 Chapter 2 Relations and Functions
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Exercise 3.1 Chapter 3 Trigonometric Functions Class 11 Maths
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